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Solve the following quadratic equation for x:
$4\sqrt{3} x^{2} +5x-2\sqrt{3} =0$
Given: Quadratic equation: $4\sqrt{3} x^{2} +5x-2\sqrt{3} =0$.
To do: To find the value of x.
Solution:
Given equation:$4\sqrt{3} x^{2} +5x-2\sqrt{3} =0$
$\Rightarrow 4\sqrt{3} x^{2} +8x-3x-2\sqrt{3} =0$
$\Rightarrow 4x\sqrt{3} x+8x-3x-2\sqrt{3} =0$
$\Rightarrow 4x\ \left(\sqrt{3} x+2\right) -\sqrt{3}\left(\sqrt{3} x+2\right) =0$
$\Rightarrow \left( 4x-\sqrt{3}\right)\left(\sqrt{3} x+2\right) =0$
If $\left( 4x-\sqrt{3}\right) =0$
$\Rightarrow x=\frac{\sqrt{3}}{4}$
If $\left(\sqrt{3} x+2\right) =0$
$\Rightarrow x=-\frac{2}{\sqrt{3}}$
$\therefore x=\frac{\sqrt{3}}{4} \ or\ -\frac{2}{\sqrt{3}}$
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