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Solve the following quadratic equation by factorization:
$x^2-(\sqrt{2}+1)x+\sqrt2=0$
Given:
Given quadratic equation is $x^2-(\sqrt{2}+1)x+\sqrt2=0$.
To do:
We have to solve the given quadratic equation.
Solution:
$x^2-(\sqrt{2}+1)x+\sqrt2=0$
$x^2-\sqrt{2}x-x+\sqrt2=0$
$x(x-\sqrt2)-1(x-\sqrt2)=0$
$(x-1)(x-\sqrt2)=0$
$x-1=0$ or $x-\sqrt2=0$
$x=1$ or $x=\sqrt2$
The values of $x$ are $1$ and $\sqrt2$.
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