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Solve the following quadratic equation by factorization:
$\sqrt{2}x^2+7x+5\sqrt2=0$
Given:
Given quadratic equation is $\sqrt{2}x^2+7x+5\sqrt2=0$.
To do:
We have to solve the given quadratic equation.
Solution:
$\sqrt{2}x^2+7x+5\sqrt2=0$
To factorise $\sqrt{2}x^2+7x+5\sqrt2=0$, we have to find two numbers $m$ and $n$ such that $m+n=7$ and $mn=\sqrt{2}\times(5\sqrt{2})=5(\sqrt2)^2=10$.
If $m=5$ and $n=2$, $m+n=5+2=7$ and $mn=(5)2=10$.
$\sqrt{2}x^2+5x+2x+5\sqrt2=0$
$\sqrt{2}x(x+\sqrt2)+5(x+\sqrt2)=0$
$(\sqrt{2}x+5)(x+\sqrt2)=0$
$\sqrt{2}x+5=0$ or $x+\sqrt2=0$
$\sqrt{2}x=-5$ or $x=-\sqrt2$
$x=-\frac{5}{\sqrt2}$ or $x=-\sqrt2$
The values of $x$ are $-\frac{5}{\sqrt2}$ and $-\sqrt2$.
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