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Solve the following quadratic equation by factorization:
$48x^2\ –\ 13x\ –\ 1\ =\ 0$
Given:
Given quadratic equation is $48x^2\ –\ 13x\ –\ 1\ =\ 0$.
To do:
We have to solve the given quadratic equation by factorization.
Solution:
$48x^2\ –\ 13x\ –\ 1\ =\ 0$
$48x^2-16x+3x-1=0$
$16x(3x-1)+1(3x-1)=0$
$(16x+1)(3x-1)=0$
$16x+1=0$ or $3x-1=0$
$16x=-1$ or $3x=1$
$x=\frac{-1}{16}$ or $x=\frac{1}{3}$
The roots of the given quadratic equation are $\frac{-1}{16}$ and $\frac{1}{3}$.  
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