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Solve the following quadratic equation by factorization:
$25x(x\ +\ 1)\ =\ –4$
Given:
Given quadratic equation is $25x(x\ +\ 1)\ =\ –4$.
To do:
We have to solve the given quadratic equation by factorization.
Solution:
$25x(x\ +\ 1)\ =\ –4$ can be written as $25x^2+25x+4=0$.
$25x^2+20x+5x+4=0$
$5x(5x+4)+1(5x+4)=0$
$(5x+1)(5x+4)=0$
$5x+1=0$ or $5x+4=0$
$5x=-1$ or $5x=-4$
$x=\frac{-1}{5}$ or $x=\frac{-4}{5}$
The roots of the given quadratic equation are $\frac{-1}{5}$ and $\frac{-4}{5}$.  
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