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Solve the following quadratic equation by factorization:
$16x\ –\ \frac{10}{x}\ =\ 27$
Given:
Given quadratic equation is $16x\ –\ \frac{10}{x}\ =\ 27$.
To do:
We have to solve the given quadratic equation by factorization.
Solution:
$16x\ –\ \frac{10}{x}\ =\ 27$ can be written as,
$x(16x-\frac{10}{x}=x(27)$ (Multiply by $x$ on both sides)
$16x^2-10=27x$
$16x^2-27x-10=0$
$16x^2-32x+5x-10=0$
$16x(x-2)+5(x-2)=0$
$(16x+5)(x-2)=0$
$16x+5=0$ or $x-2=0$
$16x=-5$ or $x=2$
$x=\frac{-5}{16}$ or $x=2$
The roots of the given quadratic equation are $\frac{-5}{16}$ and $2$. 
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