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Solve the following:$\frac{2}{3} + \frac{1}{7}$
Given :
The given expression is $\frac{2}{3} + \frac{1}{7}$.
To do :
We have to solve the given expression.
Solution :
$\frac{2}{3} + \frac{1}{7}$
As the denominators are different, take LCM to make them same.
LCM of 3 and 7 is 21.
$\frac{2}{3} + \frac{1}{7} = \frac{2\times7}{3\times7} + \frac{1\times3}{7\times3}$
$ = \frac{14}{21} + \frac{3}{21}$
$ = \frac{14+3}{21}$
$ = \frac{17}{21}$
Therefore, the value of $\frac{2}{3} + \frac{1}{7}$ is $\frac{17}{21}$
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