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Solve the following:
$\frac{-2}{3} -3 \times \frac{-2}{3} -2$
Given :
The given expression is $\frac{-2}{3} -3 \times \frac{-2}{3} -2$.
To do :
We have to solve the given expression and find the value.
Solution :
$\frac{-2}{3} -3 \times \frac{-2}{3} -2 = \frac{-2}{3} -1 \times -2 -2$
$ = \frac{-2}{3} +2 - 2$
$ = \frac{-2}{3}$
Therefore, the value of $\frac{-2}{3} -3 \times \frac{-2}{3} -2$ is $\frac{-2}{3}$.
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