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Solve the following expression.
$\frac{2x}{3}=\frac{7x}{15}+3$
Given: $\frac{2x}{3}=\frac{7x}{15}+3$
To do: Solve the given expression and find the value of $x$
Solution:
$\frac{2x}{3}=\frac{7x}{15}+3$
$\frac{2x}{3}-\frac{7x}{15}=3$
$\frac{2x\times5-7x}{15}=3$
$\frac{10x-7x}{15}=3$
$\frac{3x}{15}=3$
$3x=3\times15$
$3x=45$
$x=\frac{45}{15}$
Therefore, the value of $x=\frac{45}{15}$
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