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Solve the following
$ \frac{-4}{7}+\frac{7}{6}+\frac{2}{7}+3+\frac{(-11)}{6} $
Given: $ \frac{-4}{7}+\frac{7}{6}+\frac{2}{7}+3+\frac{(-11)}{6} $
To do: Find the value of the expression given.
Solution:
$ \frac{-4}{7}+\frac{7}{6}+\frac{2}{7}+3+\frac{(-11)}{6} $
$ \frac{-4}{7}+\frac{2}{7}+\frac{7}{6}-\frac{11}{6}+3 $
$ \frac{-2}{7}+\frac{-4}{6}+3 $
$\frac{-2\times6-4\times7+3\times42}{42}$
$\frac{-12-28+126}{42}$
$\frac{-40+128}{42}$
$\frac{88}{42}$
$\frac{44}{21}$
Therefore, the value of given expression is $\frac{44}{21}$
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