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Solve the following
$(\frac{-3}{7})^{2} $ $\div$ $(\frac{7}{3})^{\frac{12}{-4}}$
Given:
$(\frac{-3}{7})^{2} $ $\div$ $(\frac{7}{3})^{\frac{12}{-4}}$
To do: Solve the given expression.
Solution:
$(\frac{-3}{7})^{2} $ $\div$ $(\frac{7}{3})^{\frac{12}{-4}}$
= $(\frac{-3}{7})^{2}$ $\div$ $(\frac{7}{3})^{-3}$
= $(\frac{-3}{7})^{2}$ $\times$ $(\frac{3}{7})^{-3}$
= $(\frac{-3}{7})^{2}$ $\times$ $(\frac{7}{3})^{3}$
= $\frac{9}{49}$ $\times$ $\frac{49 \times7}{9 \times3}$
= $\frac{7}{3}$
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