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Solve the following:
1. $16 \div 8+10-40 \times 0$
2. $(-30) \times(-1)+100 \div 10$
Given:
\( 1.16 \div 8+10-40 \times 0 \)
\( 2 \cdot(-30) \times(-1)+100 \div 10 \)
To do:
We have to simplify the given expressions.
Solution:
We have to follow Bodmas method in these type of problems.
1.
$ \begin{array}{l}
16\div 8+10-40\times 0=\frac{16}{2} +10-0\\
\\
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =8+10\\
\ \\
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =18
\end{array}$
2.
$ \begin{array}{l}
( -30) \times ( -1) +100\div 10=30+\frac{100}{10} \ \ \ \ \ \ \ \ \ \ \ \ [( -) \times ( -) =( +)]\\
\\
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =30+10\\
\\
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =40
\end{array}$
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