Solve:$6y\ +\ \frac{1}{2}\ +\ 1\ =\ 7y\ -\ \frac{3}{3}$

Given: $6y\ +\ \frac{1}{2} \ +\ 1\ =\ 7y\ -\ \frac{3}{3}$

To find: Here we have to find the value of $y$ in the given expression $6y\ +\ \frac{1}{2} \ +\ 1\ =\ 7y\ -\ \frac{3}{3}$.

Solution:

$6y\ +\ \frac{1}{2} \ +\ 1\ =\ 7y\ -\ \frac{3}{3}$

$6y\ -\ 7y\ =\ -\ 1\ -\ \frac{1}{2} \ -\ 1$

$-\ y\ =\ -\ 2\ -\ \frac{1}{2}$

$-\ y\ =\ \frac{-\ 4\ -\ 1}{2}$

$-\ y\ =\ -\ \frac{5}{2}$

$\mathbf{y\ =\ \frac{5}{2}}$

So, value of $y$ is $\frac{5}{2}$.

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Updated on: 10-Oct-2022

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