Solve: \( \frac{0.2 y+5}{3.5 y-3}=\frac{2}{5} \)
Given:
$\frac{0.2 y+5}{3.5 y-3}=\frac{2}{5}$
To do:
We have to find the value of $y$
Solution:
$\frac{0.2 y+5}{3.5 y-3}=\frac{2}{5}$
$\Rightarrow 5(0.2y+5)=2(3.5y-3)$ [by cross multiplication]
$\Rightarrow 1y+25=7y-6$
$\Rightarrow 25+6=7y-1y$
$\Rightarrow 6y=31$
$\Rightarrow y=\frac {31}{6}$
Thus the value of $y=\frac {31}{6}$.
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