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Solve for $x$: $ 16(3 x-5)-10(4 x-8)=40 $.
Given:
\( 16(3 x-5)-10(4 x-8)=40 \).
To do:
We have to solve for $x$.
Solution:
\( 16(3 x-5)-10(4 x-8)=40 \)
$16(3)x-16(5)-10(4)x-10(-8)=40$
$48x-80-40x+80=40$ [$(-)\times(-)=(+)$]
$8x=40$
$x=\frac{40}{8}$
$x=5$
The value of $x$ is $5$.
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