Solve each of the following cryptarithms.
"

Given:

       $3  7$

$+$  $A  B$

      -----------

       $9   A$

To do:

We have to solve the given cryptarithms.

Solution:

$7+B=A$

$3+A=9$

If $A=6$ then $B=6-7=-1$ which is not possible.

This implies,

There is a carry of 1 in ten's place.

This implies,

$3+A+1=9$

$A=9-4=5$

There is a carry of 1 in ten's place.

$\Rightarrow 7+B=10+A=10+5=15$

Therefore,

$7+B=15$    

$B=15-7=8$

Tutorialspoint

Updated on: 10-Oct-2022

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