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Solve $-2(xy^2-x^2y)+5-xy$ when $x=-5$ and $y=5$.
Given:
$-2(xy^2-x^2y)+5-xy$
To do:
We have to find the value of $-2(xy^2-x^2y)+5-xy$ when $x=-5$ and $y=5$.
Solution:
We know that,
$[(+)\times(+)=(-)\times(-)=(+)]$
$[(+)\times(-)=(-)\times(+)=(-)]$
To find the value of $-2(xy^2-x^2y)+5-xy$ when $x=-5$ and $y=5$, we substitute $x=-5$ and $y=5$ in $-2(xy^2-x^2y)+5-xy$.
Therefore,
$-2(xy^2-x^2y)+5-xy=-2[(-5)(5)^2-(-5)^2(5)]+5-(-5)(5)$
$=-2[(-5)(25)-(25)(5)]+5-(-25)$
$=-2[-125-125]+5+25$
$=-2(-250)+30$
$=500+30$
$=530$
Hence, the value of $-2(xy^2-x^2y)+5-xy$ when $x=-5$ and $y=5$ is $530$.
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