Simplify the following:$\frac{a^3-b^3}{a^2+ab+b^2}$

Given :

The given expression is $\frac{a^3-b^3}{a^2+ab+b^2}$.

To do :

We have to simplify the given expression.

Solution :

$\frac{a^3-b^3}{a^2+ab+b^2}$

We know that,

$a^3-b^3= (a-b)(a^2+ab+b^2)$

$\frac{a^3-b^3}{a^2+ab+b^2}= \frac{(a-b)(a^2+ab+b^2)}{a^2+ab+b^2}$

                                            $= a-b$

Therefore, the value of $\frac{a^3-b^3}{a^2+ab+b^2}$ is $a-b$.

Tutorialspoint

Updated on: 10-Oct-2022

40 Views

Kickstart Your Career

Get certified by completing the course

Get Started