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Simplify the following expressions:$ (3+\sqrt{3})(3-\sqrt{3}) $
Given:
\( (3+\sqrt{3})(3-\sqrt{3}) \)
To do:
We have to simplify the given expression.
Solution:
We know that,
$(a+b)(a-b)=a^2-b^2$
Therefore,
$(3+\sqrt{3})(3-\sqrt{3})=(3)^{2}-(\sqrt{3})^{2}$
$=9-3$
$=6$
Hence, $(3+\sqrt{3})(3-\sqrt{3})=6$.
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