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Simplify:$ 7 \frac{1}{2}+3 \frac{1}{4}= $
Given:
\( 7 \frac{1}{2}+3 \frac{1}{4} \)
To do:
We have to find \( 7 \frac{1}{2}+3 \frac{1}{4}= \)
Solution:
$7 \frac{1}{2}+3 \frac{1}{4}=\frac{7\times2+1}{2}+\frac{3\times4+1}{4}$
$=\frac{14+1}{2}+\frac{12+1}{4}$
$=\frac{15}{2}+\frac{13}{4}$
$=\frac{15\times2+13}{4}$
$=\frac{30+13}{4}$
$=\frac{43}{4}$
Hence, $7 \frac{1}{2}+3 \frac{1}{4}=\frac{43}{4}$ .
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