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Simplify:
$3\left(\frac{-3}{2}\right) \ \div \ 6\left(\frac{-3}{2}\right)$
Given: $3\left(\frac{-3}{2}\right) \ \div \ 6\left(\frac{-3}{2}\right)$
To find: Here we have to find the value of the given expression $3\left(\frac{-3}{2}\right) \ \div \ 6\left(\frac{-3}{2}\right)$.
Solution:
$3\left(\frac{-3}{2}\right) \ \div \ 6\left(\frac{-3}{2}\right)$
$=\ \left(\frac{3\ \times \ -3}{2}\right) \ \div \ \left(\frac{6\ \times \ -3}{2}\right)$
$=\ \left(\frac{-9}{2}\right) \ \div \ \left(\frac{-18}{2}\right)$
$=\ \frac{-9}{2} \ \times \ \frac{-2}{18}$
$=\ \frac{-1}{1} \ \times \ \frac{-1}{2}$
$=\ \mathbf{\frac{1}{2}}$
So, value of the given expression is $\frac{1}{2}$.
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