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Simplify:
$\left[\frac{4}{15} \ \times \ \frac{6}{28}\right] \ \times \ \frac{9}{2}$
Given: $\left[\frac{4}{15} \ \times \ \frac{6}{28}\right] \ \times \ \frac{9}{2}$
To solve: $\left[\frac{4}{15} \ \times \ \frac{6}{28}\right] \ \times \ \frac{9}{2}$
Solution:
$\left[\frac{4}{15} \ \times \ \frac{6}{28}\right] \ \times \ \frac{9}{2}$
First solving the values inside the bracket:
$=\ \left[\frac{1}{5} \ \times \ \frac{2}{7}\right] \ \times \ \frac{9}{2}$
$=\ \frac{2}{35} \ \times \ \frac{9}{2}$
$=\ \frac{1}{35} \ \times \ \frac{9}{1}$
$=\ \mathbf{\frac{9}{35}}$
So, the answer is $\frac{9}{35}$.
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