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Simplify:
$\frac{7^8\times a^{10}b^7c^{12}}{7^6\times a^8b^4c^{12}}$
Given:
$\frac{7^8\times a^{10}b^7c^{12}}{7^6\times a^8b^4c^{12}}$
To do:
We have to simplify the given expression.
Solution:
We know that,
$\frac{a^m}{a^n}=a^{m-n}$
Therefore,
$\frac{7^8\times a^{10}b^7c^{12}}{7^6\times a^8b^4c^{12}}=7^{(8-6)}\times a^{(10-8)}b^{(7-4)}c^{(12-12)}$
$=7^2\times a^2b^3c^0$
$=49a^2b^3$ (Since $c^0=1$)
Hence, $\frac{7^8\times a^{10}b^7c^{12}}{7^6\times a^8b^4c^{12}}=49a^2b^3$.
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