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Simplify:
3. $60-80-(-8) \div 4$
4. $(-180)+6 \div 2+10$
Given:
\( 3. 60-80-(-8) \div 4 \)
\( 4 \cdot(-180)+6 \div 2+10 \)
To do:
We have to simplify the given expressions.
Solution:
We have to follow Bodmas method in these type of problems.
3.
$ \begin{array}{l}
60-80-( -8) \div 4=60-80-\left(\frac{-8}{4}\right)\\
\\
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =60-80-( -2)\\
\\
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =60-80+2\ \ \ \ \ [( -) \times ( -) =+]\\
\\
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =62-80\\
\ \\
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =-( 80-62) \ \ \ \ \ \ [ Sign\ of\ the\ larger\ number\ 80\ is\ ( -)]\\
\\
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =-18
\end{array}$
4.
$ \begin{array}{l}
( -180) +6\div 2+10=-180+\frac{6}{2} +10\\
\\
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =-180+3+10\\
\\
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =-180+13\\
\\
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =-( 180-13) \ \ \ \ \ \ \ [ Sign\ of\ the\ larger\ number\ 180\ is\ ( -)]\\
\\
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =-167\
\end{array}$