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Simplify and write in exponential form.
$ (-2)^{3} \times(-2)^{-4} $
Given:
\( (-2)^{3} \times(-2)^{-4} \)
To do:
We have to simplify and write the given expression in exponential form.
Solution:
We know that,
$a^m \times a^n = a^{m+n}$
Therefore,
$(-2)^{3} \times(-2)^{-4}=(-2)^{3+(-4)}$
$=(-2)^{-1}$
$=\frac{1}{(-2)^1}$ (Since $a^{-m}=\frac{1}{a^m}$)
$=\frac{-1}{2}$
\( (-2)^{3} \times(-2)^{-4} \) in exponential form is $(-2)^{-1}$.
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