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Represent $\sqrt{7.28}$ geometrically on the number.
Solution:
Steps of construction:-
As given number$=\sqrt{7.28}$.
$7.28$ is approximately equal to $7.30$.
1. Draw a line $AB=7.3\ units$.
2. Draw the bisector of $AB$, which bisects $AB$ at $O$.
3. Take $O$ as centre with radius $OA$, draw a semi circle which intersects $AB$ at $C$.
4. Draw a perpendicular at point $B$, which intersects the semi circle at point $D$.
5. Take point $B$, as center with radius $BD$, draw an arc which intersects line $AB$ at point $E$.
Thus, $BE=\sqrt{7.30}$.
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