Ravish wanted to make a temporary shelter for his car by making a box-like structure with tarpaulin that covers all the four sides and the top of tire car (with the front face as a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible, how much tarpaulin would be required to make (he shelter of height $2.5\ m$ with base dimensions $4\ m \times 3\ m$?
Given:
Ravish wanted to make a temporary shelter for his car by making a box-like structure with a tarpaulin that covers all four sides and the top of the tire car (with the front face as a flap which can be rolled up).
The shelter of height $2.5\ m$ with base dimensions $4\ m \times 3\ m$.
To do:
We have to find the area of the tarpaulin required.
Solution:
Length of the base $(l) = 4\ m$
Breadth of the base $(b) = 3\ m$
Height $(h) = 2.5\ m$
Therefore,
Area of tarpaulin used $=$ Area of the walls $+$ Area of the roof
$=2 h(l+b)+lb$
$=2 \times 2.5(4+3)+4 \times 3$
$=5 \times 7+12$
$=35+12$
$=47 \mathrm{~m}^{2}$
The area of the tarpaulin required is $47\ m^2$.
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