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Prove That The no. Is Irrational
Let
+√2 = a/b, where a and b are integers
so √2 = a/b - 6 = (a - 6b)/b ...this should be a rational number since all integers are there
implies √2 is a rational number which is a contradiction.
So our assumption that 6+√2 be a rational number is wrong and actually
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