PQR is a triangle, right-angled at P. If PQ=10cm and PR=24 , find QR
Given:
PQR is a triangle, right-angled at P.
PQ = 10 cm ; PR = 24 cm
To Find: The value of QR
Solution:
Since its aright angle triangle apply Pythagoras formula,
angle P = 90° ; QR is hypotenuse.
$QR^ 2 = PQ^ 2 + PR^2$
$QR^ 2 = 10^2 + 24^2$
$QR^ 2 = 100 + 576$
$QR^ 2 = 676$
$QR = \sqrt{676}$
$QR = \sqrt{26\times 26}$
$QR = 26$ cm.
Therefore the value of QR is 26 cm.
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