One Number Is 10 More Than The Other. It Their Sum Is 52.Find The Number
Given: One number is 10 more than the other and their sum is 52.
To find: We have to find the number.
Solution:
Let the first number be = a
So second number be = a + 10
Now,
=> a + a + 10 = 52
=> 2a + 10 = 52
=> 2a = 52 - 10
=> 2a = 42
$\Longrightarrow \ a\ =\ \frac{42}{2}$
=> a = 21
Therefore,
First number be = a = 21
Second number be = a + 10 = 21 + 10 = 31
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