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On a level road, a scooterist applies brakes to slow down from a speed of $10\ m/s$ to $5\ m/s$. If the mass of the scooterist and the scooter be $150\ kg$, calculate the work done by the brakes. (Neglect air resistance and friction)
Here given, mass of the scooterist and scooter $m=150\ kg$
Initial velocity of the scooter $v_1=10\ m/s$
Final velocity $v_2=5\ m/s$
Therefore, work done by the brakes to reduce the velocity of the scooter will be equal to the change of the kinetic energy of the scooter.
So, $W=K_1-K_2$
$=\frac{1}{2}m(v_1^2-v_2^2)$
$=\frac{1}{2}\times150(10^2-5^2)$
$=75\times75$
$=5625\ Joule$
Therefore, work done by the brakes to reduce the velocity of the scooter will be $5625\ Joule$.
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