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Multiply the binomials: $( 4 a+3b)$ and $( 6b-5a)$.
Given: Binomials: $( 4 a+3b)$ and $( 6b-5a)$.
To do: To multiply the binomials: $( 4a+3b)$ and $( 6b-5a)$.
Solution:
Given binomials: $( 4a+3b)$ and $( 6b-5a)$
Therefore, $( 4a+3b)( 6b-5a)=4a\times6b-5a\times4a+3b\times6b-5a\times3b$
$=24ab-20a^2+18b^2-15ab$
$=9ab-20a^2+18b^2$
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