Multiply:$(3x^2 +y^2)$ by $(2x^2 + 3y^2)$

To do:

We have to multiply $(3x^2 +y^2)$ by $(2x^2 + 3y^2)$

Solution:

We know that,

$(a+b)\times(c+d)=a(c+d)+b(c+d)$

Therefore,

$(3x^2 +y^2)\times(2x^2 + 3y^2)=3x^2 (2x^2 + 3y^2) + y^2(2x^2 + 3y^2)$

$= 6x^{2+2} + 9x^2y^2 + 2x^2y^2 + 3y^{2+2}$

$= 6x^4 + 11x^2y^2 + 3y^4$

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Updated on: 10-Oct-2022

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