Multiply:
(i) $ \frac{7}{11} $ by $ \frac{5}{4} $
(ii) $ \frac{5}{7} $ by $ \frac{-3}{4} $
(iii) $ \frac{-2}{9} $ by $ \frac{5}{11} $
(iv) $ \frac{-3}{17} $ by $ \frac{-5}{-4} $
(v) $ \frac{9}{-7} $ by $ \frac{36}{-11} $
(vi) $ \frac{-11}{13} $ by $ \frac{-21}{7} $
(vii)$ -\frac{3}{5} $ by $ -\frac{4}{7} $
(viii) $ -\frac{15}{11} $ by 7


To do:

We have to multiply the following rational numbers

Solution:

(i) Multiplying \( \frac{7}{11} \) by \( \frac{5}{4} \) 

$\frac{7}{11}\times\frac{5}{4}=\frac{7\times5}{11\times4}$

$=\frac{35}{44}$

 (ii) Multiplying \( \frac{5}{7} \) by \( \frac{-3}{4} \) 

$\frac{5}{7}\times\frac{-3}{4}=\frac{5\times(-3)}{7\times4}$

$=\frac{-15}{28}$ 

(iii) Multiplying \( \frac{-2}{9} \) by \( \frac{5}{11} \) 

$\frac{-2}{9}\times\frac{5}{11}=\frac{(-2)\times(5)}{9\times11}$

$=\frac{-10}{99}$

(iv) Multiplying \( \frac{-3}{17} \) by \( \frac{-5}{-4} \)

$\frac{-3}{17}\times\frac{-5}{-4}=\frac{(-3)\times(-5)}{17\times(-4)}$

$=\frac{15}{-68}$

$=\frac{-15}{68}$   

(v) Multiplying \( \frac{9}{-7} \) by \( \frac{36}{-11} \)

$\frac{9}{-7}\times\frac{36}{-11}=\frac{(9)\times(36)}{(-7)\times(-11)}$

$=\frac{324}{77}$ 

(vi) Multiplying \( \frac{-11}{13} \) by \( \frac{-21}{7} \)

$\frac{-11}{13}\times\frac{-21}{7}=\frac{(-11)\times(-21)}{(13)\times(7)}$

$=\frac{11\times3}{13\times1}$  

$=\frac{33}{13}$

(vii) Multiplying \( -\frac{3}{5} \) by \( -\frac{4}{7} \)

$-\frac{3}{5}\times-\frac{4}{7}=\frac{(-)\times(-)\times3\times4}{(5)\times(7)}$ 

$=\frac{12}{35}$ 

(viii) Multiplying \( -\frac{15}{11} \) by 7

$-\frac{15}{11}\times\frac{7}{1}=-\frac{15\times7}{11}$ 

$=-\frac{105}{11}$  

Updated on: 10-Oct-2022

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