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Multiply:
$(2x^2y^2 - 5xy^2)$ by $(x^2-y^2)$
To do:
We have to multiply $(2x^2y^2 - 5xy^2)$ by $(x^2-y^2)$
Solution:
We know that,
$(a+b)\times(c+d)=a(c+d)+b(c+d)$
Therefore,
$(2x^2y^2 - 5xy^2)\times(x^2-y^2)=2x^2y^2 (x^2 - y^2) - 5xy^2(x^2 - y^2)$
$= 2x^2y^2(x^2) - 2x^2y^2(y^2)- 5xy^2(x^2) + 5xy^2(y^2)$
$= 2x^{2+2}y^2- 2x^2y^{2+2}- 5x^{1+2}y^2+5xy^{2+2}$
$= 2x^4y^2-2x^2y^4-5x^3y^2+ 5xy^4$
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