![Trending Articles on Technical and Non Technical topics](/images/trending_categories.jpeg)
Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Moon revolves around the earth due to gravitational force $(F)$ of earth on moon. The work done by the gravitational force is ($r=$ radius of the circular orbit of moon)
(a) $F.2\pi r$
(b) $F.\pi r$
(c) zero
(d) negative work
As known, work done $W=F\times d\times cos\theta$
Here, $W\rightarrow$work done
$F\rightarrow$Force
$d\rightarrow$displacement
$\theta\rightarrow$ angle between the direction of acting force and the direction of the displacement
When the moon revolves around the earth it's a circular motion. And in a circular motion, the direction of the motion is always tangent to the circular path.
Therefore, $\theta=90^{o}$
Therefore, work done $W=F\times d\times cos90^o$
$=F\times d\times 0$ [$\because cos90^{o}=0$]
$=0$
Therefore, the work done by the gravitational force when the moon revolves around the earth is zero.
Therefore, option (c) is correct.
Advertisements