\( \mathrm{a}^{2}-\mathrm{b}^{2} \) is a product of ____ and ____.
Given :
$ \ ( \mathrm{a}^{2}-\mathrm{b}^{2} \ ) $
Solution :
$$\displaystyle a^{2} \ -\ b^{2} \ \ \ is\ the\ product\ of\ \ ( a+b) \ \ ( a-b) \ $$
Multiply 'a' and 'a' $$\displaystyle a\ \times \ a\ =\ a^{2}$$
Multiply 'a' and '-b' $$\displaystyle a\ \times \ -b\ =\ -\ ab$$
Multiply 'b' and 'a' $$\displaystyle a\ \times \ b\ =\ \ ab$$
Multiply 'b' and '-b' $$\displaystyle b\ \times \ -b\ =\ \ -b\ ^{2}$$
Add all the terms,
$$\displaystyle \ \ ( a+b) \ \ ( a-b) \ \ =\ \ a^{2} \ +\ ab\ -\ ab\ -\ b^{2} \ $$
$ab - ab = 0$
$$\displaystyle \ \ ( a+b) \ \ ( a-b) \ \ =\ \ a^{2} \ \ -\ b^{2} \ $$
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