Making use of the cube root table, find the cubes root of the following (correct to three decimal places)
732
Given:
732
To find:
We have to find the cube root of the given number correct to three decimal places using cube root table.
Solution:
$\sqrt[3]{732}=\sqrt[3]{73.2 \times 10}$
$=\sqrt[3]{73.2} \times \sqrt[3]{10}$
$\sqrt[3]{73}=4.179$
$\sqrt[3]{74}=4.198$
For the difference $(74-73)=1$,
The difference in the values $=4.198-4.179$
$=0.019$
This implies,
For the difference of $0.2$,
The difference in the values $=0.019 \times 0.2$
$=0.0038$
$=0.004$
Therefore,
$\sqrt[3]{73.2}=4.179+0.004$
$=4.183$
$\sqrt[3]{10}=2.154$
$\sqrt[3]{732} =\sqrt[3]{73.2} \times \sqrt[3]{10}$
$=2.154 \times 4.183$
$=9.010182$
$=9.010$
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