Making use of the cube root table, find the cubes root of the following (correct to three decimal places)
37800
Given:
37800
To find:
We have to find the cube root of the given number correct to three decimal places using cube root table.
Solution:
$\sqrt[3]{37800}=\sqrt[3]{37.8 \times 1000}$
$=\sqrt[3]{37.8} \times 10$
$\sqrt[3]{37}=3.332$
$\sqrt[3]{38}=3.362$
For the difference $(38-37)=1$,
The difference in the values $=3.362-3.332$
$=0.030$
This implies,
For the difference of $0.8$,
The difference in the values $=0.030 \times 0.8$
$=0.0240$
$=0.024$
Therefore,
$\sqrt[3]{37.8}=3.332+0.024$
$=3.356$
$\sqrt[3]{37800} =\sqrt[3]{37.8} \times 10$
$=3.356 \times 10$
$=33.56$
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