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LCM of two prime number $x$ and $y( x>y)$ is $161$. Find value of $3y-x$.
Given: The LCM of two prime numbers $x$ and $y( x>y)$ is $161$.
To do: To find the value of $( 3y-x)$.
Solution:
$161=7\times23$
So, $x=23$ and $y=7$
Therefore, $( 3y−x)=( 3\times7-23)=-2$
Updated on: 10-Oct-2022
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