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It is required to increase the velocity of a scooter of mass $80\ kg$ from $5$ to $25\ ms^{-1}$ in $2\ second$. Calculate the force required.
Here given, mass of the scooter $m=80\ kg.$
Initial velocity of the scooter $u=5\ ms^{-1}$
Final velocity of the scooter $v=25\ ms^{-1}$
Time $t=2\ s$
Therefore, acceleration $a=\frac{v-u}{t}$
$=\frac{25-5}{2}$
$=\frac{20}{2}$
$=10\ ms^{-2}$
Therefore, required force $F=ma$
$=80\ kg\times10\ ms^{-2}$
$=800\ N$
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