In the following figure, show that $ \triangle \mathrm{PSQ} $ is congruent to $ \triangle \mathrm{PSR} $.
"
Given:
$PQ=6.5\ cm$, $PR=6.5\ cm$ and $\angle PSQ=\angle PSR=90^o$.
To do:
We have to show that \( \triangle \mathrm{PSQ} \) is congruent to \( \triangle \mathrm{PSR} \).
Solution:
In triangles PQS and PSR,
$PQ=PR$ (given)
$\angle PSQ=\angle PSR=90^o$
Therefore,
$PSQ$≅$PSR$ (By RHS congruency)
Hence proved.
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