In the figure, two tangents $ A B $ and $ A C $ are drawn to a circle with centre $ O $ such that $ \angle B A C=120^{\circ} . $ Prove that $ O A=2 A B $. "
Given:
In the figure, two tangents \( A B \) and \( A C \) are drawn to a circle with centre \( O \) such that \( \angle B A C=120^{\circ} . \)
To do:
We have to prove that \( O A=2 A B \).
Solution:
In $\triangle OAB$ and $\triangle OAC$, $\angle OBA = \angle OCA - 90^o$ ($OB$ and $OC$ are radii)
$OA = OA$ (Common side)
$OB = OC$ (Radii of the circle)
$\triangle OAB\ \sim\ \triangle OAC$
$\angle OAB = \angle OAC = 60^o$
In right angled triangle $OAB$,
$\cos 60^{\circ}=\frac{AB}{OA}$
$\Rightarrow \frac{1}{2}=\frac{AB}{OA}$
$\Rightarrow OA=2AB$
Hence proved.
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