In the figure triangle $ABC$ is right-angled at $B$. Given that $AB = 9\ cm, AC = 15\ cm$ and $D, E$ are the mid points of the sides $AB$ and $AC$ respectively, calculate the length of $BC$. "
Given:
In the figure triangle $ABC$ is right-angled at $B$, $AB = 9\ cm, AC = 15\ cm$ and $D, E$ are the mid points of the sides $AB$ and $AC$ respectively.
To do:
We have to calculate the length of $BC$.
Solution:
In $\mathrm{ABC}, \angle \mathrm{B}=90^{\circ}$
$A C^{2}=A B^{2}+B C^{2}$ (Pythagonas Theorem)
$\Rightarrow B C^{2}=A C^{2}-A B^{2}$
$=(15)^{2}-(9)^{2}$
$=225-81$
$=144$
$=(12)^{2}$
$B C=12 \mathrm{~cm}$.
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