In the figure, $\triangle ABC$ is an equilateral triangle. Find $m \angle BEC$.
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Given:
In the figure, $\triangle ABC$ is an equilateral triangle.
To do:
We have to find $m \angle BEC$.
Solution:
$\triangle ABC$ is an equilateral triangle
This implies,
$\angle A = 60^o$
$ABEC$ is a cyclic quadrilateral.
Therefore,
$\angle A + \angle E = 180^o$ (Sum of opposite angles)
$60^o + \angle E = 180^o$
$\angle E = 180^0 - 60^o = 120^o$
Hence $m \angle BEC = 120^o$.
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