In the figure, rays $AB$ and $CD$ intersect at $O$.Determine $y$ when $x = 60^o$
"
Given:
Rays $AB$ and $CD$ intersect at $O$.
$x = 60^o$
To do:
We have to find the value of $y$.
Solution:
We know that,
Sum of the angles on a straight line is $180^o$.
Therefore,
$\angle AOC+\angle BOC = 180^o$
$2x + y = 180^o$
$2(60^o)+y= 180^o$
$y=180^o-120^o$
$y=60^o$
Hence, $y = 60^o$.
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