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In the figure, rays $AB$ and $CD$ intersect at $O$.Determine $x$ when $y = 40^o$"

Academic Mathematics NCERT Class 9

Given:

Rays $AB$ and $CD$ intersect at $O$.

$y = 40^o$

To do:

We have to find the value of $x$.

Solution:

We know that,

Sum of the angles on a straight line is $180^o$.

Therefore,

$\angle AOC+\angle BOC = 180^o$

$2x + y = 180^o$

$2x+40^o= 180^o$

$2x=180^o-40^o$

$2x=140^o$

$x=70^o$

Hence, $x = 70^o$.

Updated on: 10-Oct-2022

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