![Trending Articles on Technical and Non Technical topics](/images/trending_categories.jpeg)
Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
In the figure given below .Is \( A B+B C+C D+D A
answer.
Solution:
Let the diagonals AC and BD intersect in point O.
Since the sum of lengths of any two sides in a triangle should be greater than the length of the third side. Therefore,
In Δ AOB, AB < OA + OB ……….(i)
In Δ BOC, BC < OB + OC ……….(ii)
In Δ COD, CD < OC + OD ……….(iii)
In Δ AOD, DA < OD + OA ……….(iv)
⇒ AB + BC + CD + DA < 2OA + 2OB + 2OC +
2OD ⇒ AB + BC + CD + DA < 2[(AO + OC) + (DO
+ OB)] ⇒ AB + BC + CD + DA < 2(AC + BD)
Hence, it is proved.
Advertisements