In the figure, $\angle 1 = 60^o$ and $\angle 2 = (\frac{2}{3})$rd a right angle. Prove that $l \parallel m$.
"
Given:
$\angle 1 = 60^o$ and $\angle 2 = (\frac{2}{3})$rd a right angle.
To do:
We have to prove that $l \parallel m$.
Solution:
In the given figure,
Transversal $n$ intersects two lines $l$ and $m$.
$\angle 1 = 60^o$
$\angle 2 = (\frac{2}{3})90^o$
$=60^o$
This implies,
$\angle 1 = \angle 2$
$\angle 1$ and $\angle 2$ are corresponding angles
Therefore,
$l \parallel m$.
Hence proved.
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