- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- MS Excel
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP
- Physics
- Chemistry
- Biology
- Mathematics
- English
- Economics
- Psychology
- Social Studies
- Fashion Studies
- Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
In the figure, $AD \perp CD$ and $CB \perp CD$. If $AQ = BP$ and $DP = CQ$, prove that $\angle DAQ = \angle CBP$.
Given:
$AD \perp CD$ and $CB \perp CD$.
$AQ = BP$ and $DP = CQ$.
To do:
We have to prove that $\angle DAQ = \angle CBP$.
Solution:
$DP = CQ$
This implies,
$DP + PQ = PQ + CQ$
$DQ = PC$
In $\triangle ADQ$ and $\triangle BCP$
$DQ = PC$
$AQ = BP$
Therefore, by RHS axiom,
$\triangle ADQ \cong \triangle BCP$
This implies,
$\angle DAQ = \angle CBP$ (CPCT)
Hence proved.
Advertisements